–2(x – 3) ≥ 5 – (x + 3) SOMEONE PLEASE EXPLAIN STEP BY STEP SMH...
at the left side of that....use distribute multiplication while on the right side multiply -1 to x and 3 then do the operation
–2(x – 3) ≥ 5 – (x + 3) okay so its look like that now -2x + 6 ≥ 5 -1x -3 like that?
yes! you're correct! now combine like terms..
how to do that?
see those values with x? combine them at one side: either left or right...but I prefer it to be on the right side since -2x will be 2x which is greater than -x .. then those constant at the other.. NOTE: it is the same as –2(x – 3) = 5 – (x + 3)
oh so we add -2x and -1x
\[–2x + 6 ≥ 5 –x - 3\] \[ 6+3-5 \ge 2x - x\] \[4 \ge x\]
how did you get that second part??
notice that when you transfer a value to its' opposite side, it changes sign...
\[–2x + 6 ≥ 5 –x - 3\] how did go from this to this \[ 6+3-5 \ge 2x - x\]
like i said..simply combine those values with x and combine those values without x. now, i combined 6,3,and5. on the first part, notice that 3 is negative and when i transferred it to the left side it became positive... as when i transferred 5 to the left, notice that 5 became negative.
oh kk i understand now what do we do??
@unkabogable
do the operation then it will be: \[4 \ge x\]
thnx
welcome! anytime! :)
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