Question

Integration problem.

Answer 1

yay!

Answer 2

Do I need to use partial fractions here?

Answer 3

Don't worry Unkle, my questions on ODEs will end in a 2 week times, stupid repeat exam....

Answer 4

dam

Answer 5

use \[z dz = \frac{1}{2}dz^2\]

Answer 6

\[\int\frac{z}{z^2+2}\text dz\]
ok dont use partial fractions here,
remember this integral

\[\int\frac{\text dx}x=\ln z+c\]

Answer 7

let
\[x=z^2+2\]\[\text dx=...\text dz\]

Answer 8

So you are using substitution?

Answer 9

you could say that

Answer 10

have you found dx?

Answer 11

2z?

Answer 12

2zdz

Answer 13

So you int I/z dz

Answer 14

ln z +c

Answer 15

\[\frac12\int\frac{2z\cdot dz}{z^2+2}=\qquad\frac 12\int\frac{dx}{x}=\frac 12\ln x+c\]
\[=\frac12\ln (z^2+2)+c\]