Question

Solve the quardratic equation by completing the square

Answer 1

\[x ^{2}+12x+13=0\]

Answer 2

youll have to know what completing the square involves them

Answer 3

the short of it:

add a zero by, adding and subtracting the square of half the middle term

Answer 4

can you tell me the value of the middle term?

Answer 5

12

Answer 6

good, now half of 12 is?

Answer 7

6

Answer 8

almost done with the preliminaries; 6^2 is what we are after now ....

Answer 9

36

Answer 10

keep in mind that: 36-36=0
\[x ^{2}+12x+13=0\]
\[x ^{2}+12x+0+13=0\]
\[x ^{2}+12x+(36-36)+13=0\]
\[(x ^{2}+12x+36)-36+13=0\]

Answer 11

the (...) part ends up being a perfect square such that:

(x+n)^2 = x^2+12x +36 ..... n = 12/2 in this case

Answer 12

\[(x ^{2}+12x+36)-36+13=0\]
\[(x+6) ^{2}-36+13=0\]
\[(x+6) ^{2}-23=0\]

Answer 13

can you solve it from this point? or you need more help?

Answer 14

im good thanks

Answer 15

youre welcome :) and good luck