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Mathematics 10 Online
OpenStudy (anonymous):

Assume the function f(x) shown is the derivative of some function g(x). a) Tell where g(x) is increasing. b) For what value of x does g(x) have a relative minimum? c) Describe the behavior of g at x = 4. Explain how you know this would be true. See attached.

OpenStudy (anonymous):

OpenStudy (anonymous):

\(g\) is increasing on the intervals where \(f>0\) i.e . where \(f\) is above the \(x\) axis

OpenStudy (anonymous):

Can someone explain both b and c, please

OpenStudy (anonymous):

relative min means the function goes from decreasing to increasing |dw:1344717933261:dw|

OpenStudy (anonymous):

that means the derivative goes from being negative to positive look to see where the derivative crosses the \(x\) axis going from below it to above it

OpenStudy (anonymous):

looks like it does that at \(x=2\)

OpenStudy (anonymous):

so at f(2) g(x) has a relative minimum?

OpenStudy (anonymous):

right... so then

OpenStudy (anonymous):

yes, function goes from decreasing to increasing

OpenStudy (anonymous):

btw it is not at \(f(2)\) it is at \(x=2\)

OpenStudy (anonymous):

at x = 4 g(x) switches from increasing to decreasing, does that mean g(x) is concave down

OpenStudy (anonymous):

I mean f(x)*

OpenStudy (anonymous):

at \(x=4\) the function is still increasing (because the derivative is positive there)

OpenStudy (anonymous):

yes, \(f\) goes from increasing to decreasing, so you are right, the function goes from being concave up to concave down

OpenStudy (anonymous):

Okay, cool. Thanks again

OpenStudy (anonymous):

it doesn't mean the function is concave down, it means it changes concavity there yw

OpenStudy (anonymous):

Yeah, I know, should have clarified

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