question about fractional division i.e., 1/(1/3)
Originally I thought that when you get something over a fraction you want to make it into fraction * fraction i.e, in this case 1/1 * 1/3?
Apparently in this case the answer is 3, so it's goign to be 1 * 3/1 = 3?
multiply top and bottom by 3 3/3
hmm?
\[ \frac{3}{\frac{1}{3}}\cdot \frac{3}{3} \]
oh ok.
oops make that a 1 up top in the first fraction
shouldn't it be 1/(1/3)
kk
Never have seen this method, like I said normally I just flip and multiply, but I always though the num/dom was one and the next ones were just multi, but flipped.
flip and multiply is "short cut" to doing it the way I showed.
I gues smaybe because they were in paren? I feel like I've done it the other way before and it worked, so maybe I'm just thinking of that way, but continue on please.
\(\frac{1}{\frac{1}{3}}\) in english "the reciprocal of one third" or think "how many thirds are in one?"
:O that makes some sense there Satellite :).
but is that situational? On wolfram if I do 1/1/3 I get 1/3 but if I do 1/(1/3) I get 3?
thinking about is always a good option. and stick to basic principles (multiply by 1 for example) rather than tricks, if you have any doubts
On wolfram if I do 1/1/3 that is order of operations
but your method makes a lot of sense too, try to cancel out so in this case 1/3 * 3/3 = 3/(3/3) = 3/1 = 3 :)
oh okay.. stoopid wolfram :P.
\[\frac{a}{b}/\frac{c}{d}=\frac{a }{b }*\frac{d}{c} \]
So no matter what it will always be 3 huh... grr...
1/1/3 is being interpreted as \[ \frac{\frac{1}{1}}{3} \]
yuh phi :)
I knew that robto. in this case that would be 1/1/3/1 which would be 1/1 * 1/3 = 1/3...
unless there are grouping symbols, the math is read right to left. 1/1/3 is read as: 1/1 = 1, 1/3 = 1/3 1/(1/3) tells us that (1/3) is evaluated first to get a different result
pfft ... cant even get my directions correct lol; read left to right
:)
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