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ODE initial value problem
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Sub x=pi?
What you did seems correct to me.
or have I missed something @ironictoaster ?, \[\Large y^3 = - \cos (x) +c \] You can go from there and do your substitution.
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*Correction* \[ \Large y^3= -3 \cos(x) +c \]
I cancelled ^3 by ^1/3
@Spacelimbus -3cospi+c=0 c=3cospi c= approx 3
substitution will work here too, might be easier to solve then. \[\Large 0^3= -3 \cos(\pi) + c \]
\[ \therefore \ c= -3 \]
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You mean 3. You add +3cospi+C to both sides?
\[\Large \cos(\pi)=-1 \]
\[ -3 \cdot -1 = 3\]
cospi= 1 according to my calculator
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