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Mathematics 7 Online
OpenStudy (anonymous):

average rate of change

OpenStudy (anonymous):

what is the value of the average rate of change of f on [2, 5] ?

OpenStudy (anonymous):

is that the derivative?

OpenStudy (anonymous):

no, it's not .. \(\large \frac{f(5)-f(2)}{5-2} \) =

OpenStudy (anonymous):

oh just slope

OpenStudy (anonymous):

yes.. slope.

OpenStudy (anonymous):

but you have to find a c in [2, 5] such that the the derivative at c equals the slope... you're doing the Mean Value Theorem....

OpenStudy (anonymous):

which gives you 1.305 correct?

OpenStudy (anonymous):

lemme check..

OpenStudy (anonymous):

yes... 1.305

OpenStudy (anonymous):

but that's not the answer to the question....

OpenStudy (anonymous):

then what do you do?

OpenStudy (anonymous):

woudl the answer be 3.274?

OpenStudy (anonymous):

do you have the derivative of f?

OpenStudy (anonymous):

because you take the derivative then set it equal to 1.305

OpenStudy (anonymous):

yes 1 + 1/x

OpenStudy (anonymous):

yeah... that's what u do...

OpenStudy (anonymous):

1 + 1/x = 1.305 then solve to get 3.27

OpenStudy (anonymous):

and yeah.. c is about 3.27 but in exact form, c = \(\large \frac{3}{ln5-ln2} \)

OpenStudy (anonymous):

ok

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