Question

Please help! I'm having trouble with logs. Click attached :)

Answer 1

do you know the laws of logs?

Answer 2

I'm faimiliar with them, yes

Answer 3

*familiar

Answer 4

ok so one of them says that when you have log(a/b), it is the same as log(a)-log(b) ... you can apply that hear :)

Answer 5

are we okay?

Answer 6

Yes, I understand. Thanks!

Answer 7

you're welcome :)

Answer 8

what did you get though?

Answer 9

Didn't you post this same problem the other day @IloveCharlie

Answer 10

\(\text{Latex is working}\)

Answer 11

/(/large hi /) ... if this doesn't appear correctly, then i probably forgot how to write latex, if not, yay! else, :(

Answer 12

ok so it messed up.... what did i do wrong?

Answer 13

:/ I'm having trouble...

Answer 14

\(found \ what \ i \ did \ wrong \ \text{:P} \)
anyway what are you having trouble with?

Answer 15

Is it log(3.8)-log(5)?

Answer 16

@Hero Hmm... no. If so, that'd be weird. I don't think my Precal/Trig online course would repeat problems. Maybe it was something similar?

Answer 17

u said what it equal to

Answer 18

actually, no. the question has a quotient/division thingy, which obviously means there's two sides to it.

one is \(\large \sqrt{(3.2)(4.7)} \) and the other is \(\large 5 \)
according to the law, \(\large log(\frac{a}{b})=log(a) - log(b) \)
in this case, a= \(\large \sqrt{(3.2)(4.7)} \)
and b = \(\large 5 \)

hence:
\(\large log(\frac{\sqrt{(3.2)(4.7)}}{5})=log(\sqrt{(3.2)(4.7)}) - log(5) \)

=\(\large log(\sqrt{(15.04)} \ )-log(5) \)

Answer 19

are we good to go?

Answer 20

Ohhhh o.k. Now I get it. Thanks so much sasogeek

Answer 21

no problem :) you're welcome x