Question

Integrating factor answer check

Answer 1

Go for it.

Answer 2

Crap!!!

Answer 3

RHS is missing a term and I need to integ by parts I reckon.

Answer 4

what was original equation before you added integrating factor

Answer 5

There's the question.

Answer 6

yes looks like you got the right integrating factor

Answer 7

Here's my revised work.

Answer 8

How the heck to integrate the right side????

Answer 9

the (x-1) on RHS should be on top

Answer 10

So it's integration by parts?

Answer 11

yeah
\[\int\limits_{?}^{?}(x-1) \cos x = \int\limits_{?}^{?} x \cos x - \int\limits_{?}^{?} \cos x\]

Answer 12

What happens to the second term? You multiple by x^2-1 , where does the 2xy go?

Answer 13

its the reverse of the product rule...differentiate (x^2 -1)y and you will get what you started with

Answer 14

Ahh, thats clever.

Answer 15

@dumbcow

Answer 16

Disregard the 2nd line right hand side. I used int by parts.

Answer 17

looks good