Question

Help with math question? Please!
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Answer 1

"square rooting" i love it

Answer 2

this is a strange way to ask
"find \(\sqrt{2475v^{15}}\)"

Answer 3

So what would i have to do..

Answer 4

it is probably not clear how to write
\(\sqrt{2475}\) is simplest radical form, so lets hold on to that one for a moment
\(\sqrt{v^{15}}\) is much easier
two goes in to 15 7 times with a remainder of 1, so
\[\sqrt{v^{15}}=v^7\sqrt{v}\]

Answer 5

now as for
\[\sqrt{2475}\] you see all your answers have an 11 inside, so you know that
\[2475=11\times a^2\]
if you want to do a bunch of work you can factor \(2475\) or you can simply square you choices, multiply the result by 11, and see which one give you \(2475\)

Answer 6

in fact by process of elimination, you can get rid of the two with \(v^{14}\) outside the radical, because that is clearly wrong
you can also get rid of the one with 99 outside, because there is no way you are going to square that, multiply by 11, and get a result that ends in a 5

Answer 7

you can also check that
\[2475=15^2\times 11\] so
\[\sqrt{2475v^{15}}=15v^7\sqrt{11v}\]

Answer 8

That's what my first thought was! Thank you so much. you did a GREAT job explaining! :)

Answer 9

yw, glad it helped