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OpenStudy (anonymous):
Well, do you know in the equation of a line
\[y=m(x-h)+k\]
what each letter means?
OpenStudy (anonymous):
its been a long time
OpenStudy (anonymous):
Well, let's try to figure it out. How about this. Given two points, what's the slope of the line they make?
OpenStudy (anonymous):
y=mx+b
OpenStudy (anonymous):
im wrong
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OpenStudy (anonymous):
No... that's an equation for the line. How about you tell me this. If you have
\[p_1=(x, y)\]
and
\[p_2=(h, k)\], then what is the slope s you get between them?
OpenStudy (anonymous):
she just gave the slope, so that's a line
OpenStudy (anonymous):
0
OpenStudy (anonymous):
all she has to do is plug it in the slope-intercept formula
OpenStudy (anonymous):
Hmm... nvm. I was trying to teach, @panlac01 . Plug-n-chug is easy.
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OpenStudy (anonymous):
im working on a test which deadline is by 11pm pst and im desperate for any help i can get
OpenStudy (anonymous):
listen to VF
OpenStudy (anonymous):
but you almost nailed it, candrie :)
OpenStudy (anonymous):
Okay, @candrie , when you're at the y-intercept, what's the coordinate pair?
OpenStudy (anonymous):
math is tough for me
but i am awesome in english and everything else
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OpenStudy (anonymous):
Oh the problem gives it to you. What is the y-intercept pair?
OpenStudy (anonymous):
0,6?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Do you agree that the y-intercept is on the line, @candrie ?
OpenStudy (anonymous):
yes
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OpenStudy (precal):
|dw:1344737196994:dw|
in the end, remember to connect your final solution to its graph
OpenStudy (anonymous):
If a point is on a line, then its x and y values, when inserted into the formula you gave,\[y = m x +b\], must hold true.
OpenStudy (anonymous):
So put in the y-intercept's values into the formula.
OpenStudy (anonymous):
y=0(0)+6
OpenStudy (anonymous):
Well, I was trying to get you to say:
6=m(0)+b, so b = 6. But since you know what b and m are already, what's your question?
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OpenStudy (anonymous):
just needed the equation
OpenStudy (anonymous):
Well it is
y = m x + b. The difference is that my equation is
y = m (x - h) + k
But they're really the same because
y = m x - mh + k
y = m x +(k-mh)
and k-mh =b
OpenStudy (anonymous):
y=mx+b
y=0x+6
y=_____
OpenStudy (anonymous):
y=x+6?
OpenStudy (anonymous):
Multiply by 0...
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OpenStudy (anonymous):
anything multiplied to zero is _____
OpenStudy (anonymous):
0
OpenStudy (anonymous):
therefore
y=0x+6 (zero multiplied by x, plus six)
y=_____
OpenStudy (anonymous):
the final answer is your equation, the whole thing
OpenStudy (anonymous):
y=6
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OpenStudy (anonymous):
o wait
OpenStudy (anonymous):
y=0x+6?
OpenStudy (anonymous):
you got it already, but 0x can be further simplified by taking it away of the universe
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
out of the universe
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