Question

revolving

Answer 1

http://www.wolframalpha.com/input/?i=plot+y%3Dcos%5E%28-1%29x+and+y%3Dpi%2F2

Answer 2

I believe this can be done with the shell method.

Answer 3

Can you explain the shell method to me?

Answer 4

\[ \Large 2\pi \int_0^1x\cos^{-1}(x)dx \]

Answer 5

How did you do that?

Answer 6

And that equates to 2.47

Answer 7

Shell integration means

\[ \Large 2\pi \int_0^b xf(x)dx \]

Answer 8

And how do you know when to apply that?

Answer 9

I believe this can be used as a trick here because the line y= pi/2 is just the origin.

Answer 10

Revolution around the y-axis.

Answer 11

Okay. Are you sure that is the correct answer? I will try using the shell method for my other questions

Answer 12

Also, how do did you know to go to 1 for b

Answer 13

\[ \Large y= \cos ^{-1}(x) =0 \]

Answer 14

Take the cos on both sides and you will get

\[ \Large x= \cos(0)=1 \]

Answer 15

oh okay

Answer 16

do you know reimann sums?

Answer 17

For approximations?

Answer 18

yeah

Answer 19

can try, they can get a bit hard to compute.

Answer 20

alright ill post a new question