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solve −x^(2) − 5x < −6
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i have (x+6) (x-1) <0 is that correct so far?
\[-x^2-5x+6<0\rightarrow x^2+5x-6>0\rightarrow (x-1)(x+6)>0\]
yes that is very close.. you just forgot one little rule
Whenever you multiply or divide both sides by a negative number you must flip the \(\lt\) sign around
anwer \[\left( \infty, -6 \right)\cup\left( 1, \infty \right)\]
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eyust707 is athe correct?
yes
more correct \[\left( -\infty, -6 \right)\cup\left( 1, +\infty \right)\]
ahh missed that
I think you will be more familiar writng the solution like this: \[ x \gt 1 \space \space {\text or} \space \space x \lt -6 \]
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Yes, this is another record right answer.
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