Question

Help Please! if the location of a particular electron can be measured only to a precision of 0.058nm, what is the minimum uncertainty in the electrons velocity?

Answer 1

@.Sam.

Answer 2

The heisenberg uncertainty principle is just: \[x*p \ge \hbar/2\]
So here you have the constant h bar, x is position, p is momentum which if you remember is just p=mv. The mass of the electron is another constant. Simply solve for your minimum uncertainty!