Help Please! if the location of a particular electron can be measured only to a precision of 0.058nm, what is the minimum uncertainty in the electrons velocity?

Question

anonymous · Answer

@.Sam.

kainui · Answer

The heisenberg uncertainty principle is just: $$x*p \ge \hbar/2$$
So here you have the constant h bar, x is position, p is momentum which if you remember is just p=mv. The mass of the electron is another constant. Simply solve for your minimum uncertainty!