Question

Find the slope of the polar curve

Answer 1

slope of the curve is just the derivative of its equation,then substituting given point...

Answer 2

@jim_thompson5910 says there is a different way to do these questions @hartnn

Answer 3

@Hero @dumbcow @alexwee123 @UnkleRhaukus do you know how to do this?

Answer 4

i know how to do it using differentiation..if u want...

Answer 5

you are suppposed to take the derivative like this http://i.imgur.com/sHeng.png

Answer 6

i get undefined when i do that. can someone check my work

Answer 7

oh thats easier..i was going to convert equation to x and y then differentiate

Answer 8

yeah i did that for a different question oops

Answer 9

What are you guys getting?

Answer 10

ok so r = 0 when theta = pi/2
dr/d@ = 2cos(2@) -->dr/d@ = -2

this leaves
dy/dx = tan(pi/2) which is undefined
i think you did it right

now what does that mean....slope at that point is vertical

Answer 11

i get dy/dx = 5sqrt3 / 3

Answer 12

when theta = pi/6
r = sqrt3/2
dr/d@ = 1

Answer 13

\[\frac{dy}{dx} = \frac{\sin(\pi/6)+\sqrt{3}/2 \cos(\pi/6)}{\cos(\pi/6)-\sqrt{3}/2 \sin(\pi/6)} = \frac{.5 +.75}{.866-.866*.5}=2.88\]

Answer 14

you forgot dr/dtheta and r is the equation

Answer 15

dr/d@= 1

Answer 16

2 cos(theta)

Answer 17

2cos(2theta)

Answer 18

the equation was r = 2 sin theta no need for chain rule or anything

Answer 19

wait what is r?
i thought r = sin(2theta)

Answer 20

that was for the first question when you were plugging in pi/2

Answer 21

dont worry about it thanks for the help