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Mathematics 14 Online
OpenStudy (anonymous):

Please help! (-2,-2sqrt3) from rectangular coordinates to polar coordinates? a. (4, 120°) b. (4, 150°) c. (4, 210°) d. (4, 240°)

OpenStudy (kainui):

So the x and y coordinates, how might you translate that into a single line from the center? You can use the pythagorean theorem since the distance to that point from the origin is just a hypotenuse of a triangle with a height of y and length of x. Now how do you find the angle? Well what function gives you an angle? Inverse trig functions. What information do you have to find that? The x and y, which is the same as the opposite and adjacent sides ins SOH CAH TOA, so we can see we'll be using inverse tangent to find the angle!

OpenStudy (anonymous):

Oh o.k. Makes sense! Can you please go through solving step by step with me though? I'm having lots of trouble :/

OpenStudy (kainui):

Sure, show me your work and try it out and I'll help you along.

OpenStudy (anonymous):

Is it b.?

OpenStudy (kainui):

So basically when you look at the point on a graph, it looks like this: |dw:1344760137564:dw| and it's 4 away and 60 degrees below the x-axis, however...

OpenStudy (anonymous):

|dw:1344759518723:dw| Like Kainui said, think of this as a triangle. The A here correlates to your x length from the origin (-2), B correlates to your y distance from the origin (-2√3). What I would do first is find out your C value using the Pythagorean theorem: A^2 + B^2 = C^2 (-2)^2 + (-2√3)^2 = C^2 4 + 12 = C^2 16 = C^2 4 = C Then find out what your theta value is by using trigonometric identities. |dw:1344759887906:dw| Opposite/adjacent is the role of tangent, so we have: tan(θ) = B/A tan(θ) = (2√3)/2 θ = tan^-1[(2√3)/2] θ = π/3 Since we know that one π is equivalent to 180°, we can easily reason that π/3 is equivalent to 60° meaning your total angle is 240°, and your distance out is 4. In polar form, (-2, -2√3) correlates to (4, 240°).

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