Question

find the range of the given function
f(x)=(x-[x])/(1+x-[x])

Answer 1

is that floor function?

Answer 2

Dont know

Answer 3

[x] ? i think its greatest integer smaller than or equal to x

Answer 4

do u know properties of that function?

Answer 5

It is greatest integer function

Answer 6

like [3.5]=3

Answer 7

yes

Answer 8

[-2.1] ?

Answer 9

-3

Answer 10

answer to my question

Answer 11

so u must know that \(0\le x-[x] < 1\)

Answer 12

I am a mathematician so i know about it

Answer 13

@Joseph91 if some one is helping you so be nice to him or leave hopes from us to be polite with you ...

Answer 14

You are lucky that mukushla is helping you .. he is great in mathematics but he can only explain you if you will be nice to him

Answer 15

hint:

let \(t=x-[x]\) then u have \[f(t)=\frac{t}{1+t}\] with \(0 \le t \le1\)

i hope u can find range of later function

Answer 16

sorry \(0 \le t <1\)

Answer 17

so what you had done nothing on it

Answer 18

\[f(t)=1-\frac{1}{1+t}\]\[ 1 \le 1+t<2\]now what?

Answer 19

[0,?)

Answer 20

it is not the answer sir the answer is [0,0.5)

Answer 21

i dont know how

Answer 22

so see this

\[0 \le t<1\]\[1 \le t+1<2\]\[\frac{1}{2} < \frac{1}{1+t}\le1\]\[-1 \le -\frac{1}{1+t}<-\frac{1}{2}\]\[0 \le 1-\frac{1}{1+t}<\frac{1}{2}\]\[0 \le f(t)<\frac{1}{2}\]

Answer 23

is that right?

Answer 24

cheking

Answer 25

Great

Answer 26

so who are you sir? you solved it very easily!

Answer 27

sorry about the questions... i just wanted to know what is your level