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Mathematics 6 Online
OpenStudy (anonymous):

Find the condition that x^n + y^n may be divisible by x + y.

OpenStudy (anonymous):

IF n is odd

OpenStudy (anonymous):

How do you prove that?

OpenStudy (anonymous):

sum of odd roots factor always factor out (x+y)

OpenStudy (anonymous):

What do you mean by that?

OpenStudy (anonymous):

I know how, PLZ wait sec trying to write it down

OpenStudy (anonymous):

Oh got it.... let f(x)=x^n + y^n

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

So you should use factor theorem for this?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

now, when f(x) is divided by (x+y) then REMAINDER = f(-y) = (-y)^n + y^n

OpenStudy (anonymous):

ok got that.

OpenStudy (anonymous):

Now, for x^n + y^n to be divisible by x + y.. remainder = 0 or, (-y)^n + y^n=0

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

which is only possible when n is odd

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

ok so when n is odd, (-y)^n = -y so (-y)^n + y^n = -y + y = 0 thanks!!

OpenStudy (anonymous):

oh its like this: when n is odd, (-y)^n = -(y)^n so (-y)^n + y^n = -(y)^n + y^n = 0

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