What is the solution set of |x – 2| > 3?
define when x is equal to 3 for a boudary position
boundary that is :)
|x-2| = 3 ....
I'm sorry I don't get it ;w; On my homework sheet it has two solutions for answers. x < 1 or x > –5 x < –1 or x > 5 x > 1 or x < –5 x > –1 or x < 5
I don't get how I'm supposed to find two answers.
do you recall what an absolute value represents?
The distance from 0?
absolute values measure distance, not direction is a good way to remember it :) 3 feet to the left is the same distance as 3 feet from the right, so in math terms we ignore the sign |-3| = |3| = 3 so, we have to find values such that |x-2| = 3, then x-2 = 3 or x-2 = -3 both fit the bill
graphically it looks like this|dw:1344785860053:dw|
there are two solutions that satisfy the condition
So -1 and 5
good, now since we are looking for 1 variable; lets use 1 line to represent it and mark it with -1, 0 , and 5
|dw:1344786022589:dw| when x=0, what do we get?
|x-2| = n when x=0?
n = 2
very good, lets use that to our advantage|dw:1344786183648:dw|
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