What are the possible rational zeros of f(x) = 2x3 - 4x2 - 7x + 14?
a) 1/2, 1, 2 , 7/2, 7, 14 b) ± 1, ± 2, ± 7, ± 14 c) ± 1/2, ± 1, ± 2, ± 7/2, ± 7, ± 14 d) 1, 2, 7, 14 i got the answer for c? i'm not sure if it's correct.
How did you obtain (c) as your answer? What steps did you take to get there?
to be honest, i'm not really sure what i did.
Ok. fair' nuff. :) You want to use the rational root theorem here. http://www.purplemath.com/modules/rtnlroot.htm is a very good set of notes (I'd recommend bookmarking it). Here's the general list you should make when solving a problem like this: f(x) = 2x^3 - 4x^2 - 7x + 14 Constant term = 14 Factors of 14 = 1, 2, 7, 14 Highest power of x is 3. Coefficient of x^3 is 2 Factors of 2 = 1,2 Now the rest should follow from the rational root theorem.
okay thank you!
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