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Mathematics 15 Online
OpenStudy (anonymous):

What are the possible rational zeros of f(x) = 2x3 - 4x2 - 7x + 14?

OpenStudy (anonymous):

a) 1/2, 1, 2 , 7/2, 7, 14 b) ± 1, ± 2, ± 7, ± 14 c) ± 1/2, ± 1, ± 2, ± 7/2, ± 7, ± 14 d) 1, 2, 7, 14 i got the answer for c? i'm not sure if it's correct.

OpenStudy (mathteacher1729):

How did you obtain (c) as your answer? What steps did you take to get there?

OpenStudy (anonymous):

to be honest, i'm not really sure what i did.

OpenStudy (mathteacher1729):

Ok. fair' nuff. :) You want to use the rational root theorem here. http://www.purplemath.com/modules/rtnlroot.htm is a very good set of notes (I'd recommend bookmarking it). Here's the general list you should make when solving a problem like this: f(x) = 2x^3 - 4x^2 - 7x + 14 Constant term = 14 Factors of 14 = 1, 2, 7, 14 Highest power of x is 3. Coefficient of x^3 is 2 Factors of 2 = 1,2 Now the rest should follow from the rational root theorem.

OpenStudy (anonymous):

okay thank you!

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