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OpenStudy (anonymous):

A H2 molecule is exposed to a radiation of wave lenght 250nm if the dissociation energyof H2 is 7.15*10^-19 j/molecule the K.E is?

OpenStudy (anonymous):

@experimentX

OpenStudy (anonymous):

@experimentX @experimentX

OpenStudy (experimentx):

250 nm = hv = hc/250*10^-9 KE should be hc/250*10^-9 - 7.15*10^-19

OpenStudy (experimentx):

if not ... reduce 2*13.6 ev ... from the energy of radiation

OpenStudy (anonymous):

7.9 -7.15 =0.75 but it is wrong

OpenStudy (anonymous):

the answer should be 7.7 *10^-20j

OpenStudy (anonymous):

u got it ....

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