Question

A H2 molecule is exposed to a radiation of wave lenght 250nm if the dissociation energyof H2 is 7.15*10^-19 j/molecule the K.E is?

Answer 1

@experimentX

Answer 2

@experimentX @experimentX

Answer 3

250 nm = hv = hc/250*10^-9
KE should be hc/250*10^-9 - 7.15*10^-19

Answer 4

if not ... reduce 2*13.6 ev ... from the energy of radiation

Answer 5

7.9 -7.15 =0.75 but it is wrong

Answer 6

the answer should be 7.7 *10^-20j

Answer 7

u got it ....

Answer 8

http://www.wolframalpha.com/input/?i=6.62*10^-34*3*10^8+%2F%28250*10^-9%29+-+7.15*10^-19