write the first five terms for the sequence an=n(n+1)
find value of an for n=1, n=2, n=3, n=4 and n=5
is it 2,5,7,9,11
nope
check out your second term
and all the remaining terms
putting n=2 gives you an= 2*(2+1)
4
nope ..it's 2*3=6
how
nvm lol
solve the brackets first then multiply the outcome of bracket by2 like 2+1=3 and multiplied by 2=6
i get it idk what i was looking at
a1=2 a2=2*3=6 a3=3*4=12 a4=4*5=20 a5=5*6=30
what about this an=(-2)^n
what do I do
just put n=1,2,3,4,5 and so on.....like (-2)^1=-2 but in case of even power result will be positive
so sombody told me its -2,4,-8,16,-32 but i dont understand when you plug those numbers in you dont get those unless you plug in the answer of what you got before
a1=(-2)^1=-2 a2=(-2)^2=4 a3=(-2)^3=8 . . . . .
make sure you have the proper starting value of "n"; some texts say 1, others say 0
omg idk what im thinking im so lost today lol thanks really
ohhh sry..... a3=(-2)^3=-8
Yah i got it i was thinking times each other not to the power
Now for something like this what do I do same question as befoe a2=10, d=-2
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