just read this short thing. It seriously clarifies everything
OpenStudy (anonymous):
okay thank you
OpenStudy (swissgirl):
but basically its the inverse of squaring \(3^2=9 \) so \( \sqrt{9} =3 \)
The was i look at square root is there a number that when you multiply it by itself it will give you that original number
OpenStudy (swissgirl):
so for example \( \sqrt{16}\)
What number when you multiply it by itself will give you 16
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OpenStudy (swissgirl):
1*1=1
2*2=4
3*3=9
4*4=16
OpenStudy (swissgirl):
We see that when we multiply 4 buy itself it will give you 16
\( \sqrt{16}=\sqrt{4*4}=4
OpenStudy (swissgirl):
\( \sqrt{16} = \sqrt{4*4}=4 \)
OpenStudy (swissgirl):
ok Ill give you an example
what is \( \sqrt{25}=?\)
OpenStudy (anonymous):
5
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OpenStudy (swissgirl):
YAHOOOOOOO
OpenStudy (anonymous):
lol :)
OpenStudy (swissgirl):
hahah its hard to explain this topic when like its not in person
OpenStudy (swissgirl):
ok so lets start with \(\sqrt{s^4} \)
how can that be rewritten?
OpenStudy (swissgirl):
\( \large \sqrt{s*s*s*s} = \sqrt{s^4} \)
did you follow this?
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OpenStudy (swissgirl):
@amistre64 maybe you can do a better job explaining
OpenStudy (amistre64):
i dunno if a can splain it better, but if you realize that radicals are frational exponents it might be better to see
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OpenStudy (swissgirl):
ohh this way is simplerrrrrrrr
OpenStudy (anonymous):
and yea i understood that!
OpenStudy (amistre64):
lets see hoe it plays then :)
\[\sqrt{s^8}+\sqrt{25^8}+2\sqrt{s^8}+\sqrt{s^4}\]
\[s^{8/2}+\sqrt{25}s^{8/2}+2s^{8/2}+s^{4/2}\]
\[s^4+\sqrt{25}s^4+2s^4+s^2\]
OpenStudy (amistre64):
err... *how it plays out lol
OpenStudy (swissgirl):
you can pull out the 25
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OpenStudy (amistre64):
you can, but i like to leave something to the imagination ;)