f-2 f+1
--- + ---
f-4 f+2

Question

f-2       f+1
---  + ---
f-4       f+2

swissgirl · Answer

when adding fractions we need to have the same  denomanator
Our denomators are (f-4) and (f+2)
So a common denomator for both is (f-4)(f+2)

swissgirl · Answer

S our first fraction the denomanator is (f-4) so we wld need to multiply it by $\large {(f+2) \over (f+2) }$

swissgirl · Answer

did you follow?

anonymous · Answer

yea

swissgirl · Answer

okkk ill just show u what to do

anonymous · Answer

ok

swissgirl · Answer

sorry to many things going on at once ok now ill show u

swissgirl · Answer

$ \large { f-2 \over f-4} * {f+2 \over f+2} + {f+1 \over f+2} * {f-4 \over f-4} $

$ \large { (f-2)(f+2) \over (f-4)(f+2)} + {(f+1)(f-4) \over (f-4)(f+2)} $

$ \large {(f-2)(f+2)+(f+1)(f-4) \over (f-4)(f+2)} $

$ \large { (f^2-4) + (f^2-3f-4) \over (f-4)(f+2) } $

$ \large { 2f^2-3f-8 \over (f-4)(f+2) } $
and that is your answer

swissgirl · Answer

Sorry that it took long just doing a few things at once