Question

\[\sqrt{s^8}+\sqrt{25^8}+2\sqrt{s^8}+\sqrt{s^4}\]

Answer 1

Find the exact value of the radical expression in simplest form

Answer 2

help please :)

Answer 3

First combine like terms to get and change to exponential notation:\[3s ^{(8/2)}+s ^{(4/2)}+25^{(8/2)}\]

Answer 4

okay...yea?

Answer 5

Simplify to get:
\[3s ^{4}+s ^{2}+390625\]

Answer 6

That last number is huge, are you sure it was the square root of 25 to the 8th?

Answer 7

let me see

Answer 8

yea 25s^8

Answer 9

Okay... you need to factor after using a u substitution for s^2 and u^2=s^4 giving:
\[3u ^{2}+u +390625\]
Make sure they are regular square roots to start and not 4th roots too.

Answer 10

I'm going too far... if this is not set to zero, we can't solve for s... the answer above is your simplest form (before the u substitution):\[3s ^{4}+s ^{2}+390625\]

Answer 11

but thats not in the answer choice

Answer 12

noo she wrote it incorrect

Answer 13

lol i did?

Answer 14

s^4 + 25^4 + 2s^4 + s^2

Answer 15

more to do

Answer 16

\( \large\sqrt{s^8} + \sqrt{25s^8} + s\sqrt{s^8} +\sqrt{s^4} \)

Answer 17

yes ^^

Answer 18

if you want the answer i can give it to u :P lol
\( s^4+5s^4+2s^4+s^2 \)
\( 8s^4+s^2 \)
That is your answer

Answer 19

thank you!

Answer 20

lol, well that makes a difference

Answer 21

there is a missing s in the second term!!

Answer 22

According to the answer that Swissgirl gave, her original statement of the true question was also incorrect, but very close.
One of the s' should be a two:
\[\sqrt{s ^{8}}+\sqrt{25s ^{8}}+2\sqrt{s ^{8}}+\sqrt{s ^{4}}\]then go to Swissgirl's final solution.

Answer 23

ya it was an accident it shld have been a 2
I had solved this question b4 but I guess the user didnt follow my explanation so i just decided to give the answer

Answer 24

ty