OpenStudy (anonymous):

HELPPP!! Solve this equation algebraically - 2^x+2^-x=5

5 years ago
OpenStudy (anonymous):

2^x + 1/2^x = 5 (2^x)^2 + 1 = 5 (2^x) ??

5 years ago
OpenStudy (anonymous):

(2^x)= ???

5 years ago
OpenStudy (anonymous):

\[2^x + 2^{-x} = 5 = 2^x + \frac{1}{2^x}\] \[(5) 2^x = 2^x 2^x + 1\]

5 years ago
OpenStudy (anonymous):

\[\log 5 + x(\log 2) = 2x(\log 2) + \log(1) = 2x(\log 2)\]

5 years ago
OpenStudy (anonymous):

thank youuu

5 years ago
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