OpenStudy (anonymous):

which of the following is a point in the intersection of x^2 + y^2 < 4 and x - 3y < -3? (a) (0, 1) (b) (1, -1) (c) (1, 0) (d) (-1, 1) (e) (0, 0)

5 years ago
OpenStudy (anonymous):

Good question! We have a circle with radius = 2 and what else? what is the second thing?

5 years ago
OpenStudy (anonymous):

why not sketch it?

5 years ago
OpenStudy (anonymous):

The second inequality is tricky x - 3y < -3 (1/3)x - y < -1 y > (1/3)x + 1

5 years ago
OpenStudy (anonymous):

|dw:1344820005681:dw|

5 years ago
OpenStudy (anonymous):

Not sure exactly where the line goes yet.

5 years ago
OpenStudy (anonymous):

I've drawn it badly, the y-intercept is 1, the x-intercept is -3. So it should cross the circle at positive y.

5 years ago
OpenStudy (anonymous):

You there?

5 years ago
OpenStudy (anonymous):

yeah

5 years ago
OpenStudy (anonymous):

Now, the question is pretty easy I think. (0,1) won't do b/c it doesn't satisfy y > (1/3)x + 1 it satisfies = but not >

5 years ago
OpenStudy (anonymous):

Only -1, 1 looks possible.

5 years ago
OpenStudy (anonymous):

And I should've said, they are all inside the circle.

5 years ago
OpenStudy (anonymous):

ok thank you so much

5 years ago
OpenStudy (anonymous):

yw

5 years ago