Question

another long one. the speed of train A is 14 mph slower than train B. Train A travels 200 miles the same time that it takes B to travel 270 miles. What are the speeds of each train. Help.

Answer 1

well,the times are equal, correct? and distance = speed * time. Where do you go from there?

Answer 2

im honestly lost :(

Answer 3

I will try to explain this a little better for you if you are having trouble.
Let Da = distance traveled by train A
Db = distance traveled by train b
Va = speed of train A
Vb = speed of train B
t = time

okay so you can start out using distance = speed * time, or d=vt
times the trains spent traveling are both equal, so rearranging the equations:
Da=Va*t
Db=Vb*t
into:
t=Da/Va
t=Db/Vb
will allow you to set them equal to each other, giving you:

Da/Va=Db/Vb.

It was said in the problem that Train a was moving 14 mph slower, so lets change our Va and Vb to reflect this
Vb = V
Va= (V-14)
and substitute your distance values
Da = 200 mi
Db = 270 mi

that gives us:
200/(V-14) = 270/V
200V=270(V-14)
200V = 270V - 3780
70V = 3780
that would mean V = 54mph

since V = Vb, Vb = 54 mph.
Va = 40 mph

Answer 4

thanks alot