Question

Simplify the expression (3n^2)^3

Answer 1

ok, do you have any clue on how to solve this?

Answer 2

Yeah I just don't know if 3 is raised to the 3rd power

Answer 3

\[(3n ^{2})^{3}\]
= \[3^{3}n ^{2 \times 3} \]
= \[27n ^{6}\]

Answer 4

yep, it is.

Answer 5

do you understand my working?

Answer 6

Yea, can you help me with this one (3m^1/2•27n^1/4)^4

Answer 7

it's that, correct?

Answer 8

No it's 3m^1/2 and 27n^1/4

Answer 9

Yea sorry I'm just on my phone so it's a bit slow, it's like this (3m ^(1/2) •27n^(1/4)^4

Answer 10

\[3m ^{1/2} \times 27n ^{1/4} \]
\[3m ^{1/2} \times 27n ^{1/256} \]
\[\sqrt{3m}.\sqrt[256]{27n}\]

Answer 11

The first step I was unable to type ^4 additionally to the (1/4) power, sorry, but as you can see I have expanded as normal with the ^4.

Answer 12

@robtobey, is my working correct?

Answer 13

I got\[81 \sqrt{m}* n^{1/256} \]

Answer 14

yeh, u should be right.

Answer 15

How did you get 1/256?

Answer 16

(1/4)^4

Answer 17

\[(3*m){}^{\wedge}(1/2)*27*n{}^{\wedge}(1/4){}^{\wedge}4=27 \sqrt{3} *\sqrt{m}* n^{1/256} \]

Answer 18

\[3m ^{1/2} \times 27n ^{1/4} \]
\[m ^{1/2} = \sqrt{m}\]
\[81\sqrt{m}*n ^{1/256}\]

Answer 19

Oh okay I see now thank you