Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

Help solve: 3(t+5)-1>t-2(1-t) A.) all real numbers B.) no solution C.) (t:t>-16) D.) (t:t>0)

OpenStudy (anonymous):

also.... explain to me what all real numbers mean and no solution...anyone please help!

OpenStudy (anonymous):

callisto help

jimthompson5910 (jim_thompson5910):

what does 3(t+5) distribute to

OpenStudy (anonymous):

thats how the question is written... it doesnt give the value of t

jimthompson5910 (jim_thompson5910):

3(t+5) 3*t+3*5 ... Distribute here 3t + 15 ... Multiply

jimthompson5910 (jim_thompson5910):

So 3(t+5) distributes to 3t + 15

OpenStudy (anonymous):

yeah i know that, but look at the answers. im not sure what it was be?

OpenStudy (anonymous):

*would

jimthompson5910 (jim_thompson5910):

alright, then what does -2(1-t) distribute to

OpenStudy (anonymous):

-2 + 2t

jimthompson5910 (jim_thompson5910):

So we have this so far 3(t+5)-1>t-2(1-t) 3t+15-1>t-2+2t

jimthompson5910 (jim_thompson5910):

now combine like terms

OpenStudy (anonymous):

3t-14>3t-2

jimthompson5910 (jim_thompson5910):

good, now what's next?

OpenStudy (anonymous):

im not sure

jimthompson5910 (jim_thompson5910):

Can we add or subtract anything from both sides?

OpenStudy (anonymous):

yeah we can add a two to both sides... but can we subtract the 3t even though it would cancel it out?

jimthompson5910 (jim_thompson5910):

I'm leaning towards subtracting 3t from both sides (you can add 2, but that's not really relevant)

OpenStudy (anonymous):

how do u get 3t +14?

jimthompson5910 (jim_thompson5910):

oh my bad, made a typo

jimthompson5910 (jim_thompson5910):

i didn't mean to type 3t - 14

OpenStudy (anonymous):

so what is it exactly?

jimthompson5910 (jim_thompson5910):

3t+14>3t-2 3t+14 -3t > 3t-2 -3t ... Subtract 3t from both sides 14 > -2 ... Subtract

jimthompson5910 (jim_thompson5910):

What do you notice about the last inequality?

jimthompson5910 (jim_thompson5910):

for some reason, i glossed over when you wrote 3t-14, it should be 3t+14

OpenStudy (anonymous):

14 is greater than -2

jimthompson5910 (jim_thompson5910):

is that always true, sometimes true, or never true

OpenStudy (anonymous):

its true

OpenStudy (anonymous):

what does all real numbers mean?

jimthompson5910 (jim_thompson5910):

basically any number you can think of is a real number

OpenStudy (anonymous):

always true

jimthompson5910 (jim_thompson5910):

you'll learn about numbers that are known as complex numbers and these numbers aren't real numbers

jimthompson5910 (jim_thompson5910):

but that's later down the road

jimthompson5910 (jim_thompson5910):

so 3(t+5)-1>t-2(1-t) is always true

jimthompson5910 (jim_thompson5910):

since so 3(t+5)-1>t-2(1-t) is always true, this means any real number satisfies the inequality

jimthompson5910 (jim_thompson5910):

So the answer is choice A) all real numbers

OpenStudy (anonymous):

ok can u help me with another question really quick... i think u would be a good help

jimthompson5910 (jim_thompson5910):

Here's the full step by step solution (in one complete post). This will be for you to take notes from. 3(t+5)-1>t-2(1-t) 3t+15-1>t-2+2t 3t+14>3t-2 3t+14 -3t > 3t-2 -3t ... Subtract 3t from both sides 14 > -2 ... Subtract Since the last inequality is always true (regardless of the value of t), this means that the original inequality is always true (regardless of the value of t) So any real number satisfies the inequality 3(t+5)-1>t-2(1-t) So the answer is choice A) all real numbers

jimthompson5910 (jim_thompson5910):

whats your other question

OpenStudy (anonymous):

actually 2 questions: absolute value of (3p-3/5)>6/5

jimthompson5910 (jim_thompson5910):

| 3p-3/5 | > 6/5 breaks down to 3p-3/5 > 6/5 or 3p-3/5 < -6/5 From here, solve each equation for p to get your two answers

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

let me know what you get

OpenStudy (anonymous):

p>8/15 and ...

jimthompson5910 (jim_thompson5910):

close, but it's not 8

OpenStudy (anonymous):

oh typo...9/15

OpenStudy (anonymous):

y do you change the 6/5 to negative and positive?

jimthompson5910 (jim_thompson5910):

good fix

jimthompson5910 (jim_thompson5910):

you can then reduce 9/15 to what?

jimthompson5910 (jim_thompson5910):

Because |x| > k implies that x > k or x < -k for some positive number k

OpenStudy (anonymous):

1/5 and the other is 1/5

jimthompson5910 (jim_thompson5910):

both are 1/5?

OpenStudy (anonymous):

no 3/5 and -1/5 i think

jimthompson5910 (jim_thompson5910):

good, that's part of it

jimthompson5910 (jim_thompson5910):

how do the signs fit in?

OpenStudy (anonymous):

p>3/5 and p<1/3

jimthompson5910 (jim_thompson5910):

first part is correct, second is not

jimthompson5910 (jim_thompson5910):

btw, you say "or" instead of "and"

OpenStudy (anonymous):

-1/5

jimthompson5910 (jim_thompson5910):

better, so its p > 3/5 or p < -1/5

OpenStudy (anonymous):

k thx... i dont need help on the other question cuz i understand it now... ur a good helper... help me next time!! lol

jimthompson5910 (jim_thompson5910):

I'm glad you think so and that it's starting to click for you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!