Help solve:
3(t+5)-1>t-2(1-t)
A.) all real numbers
B.) no solution
C.) (t:t>-16)
D.) (t:t>0)
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OpenStudy (anonymous):
also.... explain to me what all real numbers mean and no solution...anyone please help!
OpenStudy (anonymous):
callisto help
jimthompson5910 (jim_thompson5910):
what does 3(t+5) distribute to
OpenStudy (anonymous):
thats how the question is written... it doesnt give the value of t
jimthompson5910 (jim_thompson5910):
3(t+5)
3*t+3*5 ... Distribute here
3t + 15 ... Multiply
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jimthompson5910 (jim_thompson5910):
So 3(t+5) distributes to 3t + 15
OpenStudy (anonymous):
yeah i know that, but look at the answers. im not sure what it was be?
OpenStudy (anonymous):
*would
jimthompson5910 (jim_thompson5910):
alright, then what does -2(1-t) distribute to
OpenStudy (anonymous):
-2 + 2t
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jimthompson5910 (jim_thompson5910):
So we have this so far
3(t+5)-1>t-2(1-t)
3t+15-1>t-2+2t
jimthompson5910 (jim_thompson5910):
now combine like terms
OpenStudy (anonymous):
3t-14>3t-2
jimthompson5910 (jim_thompson5910):
good, now what's next?
OpenStudy (anonymous):
im not sure
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jimthompson5910 (jim_thompson5910):
Can we add or subtract anything from both sides?
OpenStudy (anonymous):
yeah we can add a two to both sides... but can we subtract the 3t even though it would cancel it out?
jimthompson5910 (jim_thompson5910):
I'm leaning towards subtracting 3t from both sides (you can add 2, but that's not really relevant)
OpenStudy (anonymous):
how do u get 3t +14?
jimthompson5910 (jim_thompson5910):
oh my bad, made a typo
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jimthompson5910 (jim_thompson5910):
i didn't mean to type 3t - 14
OpenStudy (anonymous):
so what is it exactly?
jimthompson5910 (jim_thompson5910):
3t+14>3t-2
3t+14 -3t > 3t-2 -3t ... Subtract 3t from both sides
14 > -2 ... Subtract
jimthompson5910 (jim_thompson5910):
What do you notice about the last inequality?
jimthompson5910 (jim_thompson5910):
for some reason, i glossed over when you wrote 3t-14, it should be 3t+14
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OpenStudy (anonymous):
14 is greater than -2
jimthompson5910 (jim_thompson5910):
is that always true, sometimes true, or never true
OpenStudy (anonymous):
its true
OpenStudy (anonymous):
what does all real numbers mean?
jimthompson5910 (jim_thompson5910):
basically any number you can think of is a real number
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OpenStudy (anonymous):
always true
jimthompson5910 (jim_thompson5910):
you'll learn about numbers that are known as complex numbers and these numbers aren't real numbers
jimthompson5910 (jim_thompson5910):
but that's later down the road
jimthompson5910 (jim_thompson5910):
so 3(t+5)-1>t-2(1-t) is always true
jimthompson5910 (jim_thompson5910):
since so 3(t+5)-1>t-2(1-t) is always true, this means any real number satisfies the inequality
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jimthompson5910 (jim_thompson5910):
So the answer is choice A) all real numbers
OpenStudy (anonymous):
ok can u help me with another question really quick... i think u would be a good help
jimthompson5910 (jim_thompson5910):
Here's the full step by step solution (in one complete post). This will be for you to take notes from.
3(t+5)-1>t-2(1-t)
3t+15-1>t-2+2t
3t+14>3t-2
3t+14 -3t > 3t-2 -3t ... Subtract 3t from both sides
14 > -2 ... Subtract
Since the last inequality is always true (regardless of the value of t), this means that the original inequality is always true (regardless of the value of t)
So any real number satisfies the inequality 3(t+5)-1>t-2(1-t)
So the answer is choice A) all real numbers
jimthompson5910 (jim_thompson5910):
whats your other question
OpenStudy (anonymous):
actually 2 questions:
absolute value of (3p-3/5)>6/5
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jimthompson5910 (jim_thompson5910):
| 3p-3/5 | > 6/5
breaks down to
3p-3/5 > 6/5 or 3p-3/5 < -6/5
From here, solve each equation for p to get your two answers
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
let me know what you get
OpenStudy (anonymous):
p>8/15 and ...
jimthompson5910 (jim_thompson5910):
close, but it's not 8
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OpenStudy (anonymous):
oh typo...9/15
OpenStudy (anonymous):
y do you change the 6/5 to negative and positive?
jimthompson5910 (jim_thompson5910):
good fix
jimthompson5910 (jim_thompson5910):
you can then reduce 9/15 to what?
jimthompson5910 (jim_thompson5910):
Because |x| > k implies that
x > k or x < -k
for some positive number k
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OpenStudy (anonymous):
1/5 and the other is 1/5
jimthompson5910 (jim_thompson5910):
both are 1/5?
OpenStudy (anonymous):
no 3/5 and -1/5 i think
jimthompson5910 (jim_thompson5910):
good, that's part of it
jimthompson5910 (jim_thompson5910):
how do the signs fit in?
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OpenStudy (anonymous):
p>3/5 and p<1/3
jimthompson5910 (jim_thompson5910):
first part is correct, second is not
jimthompson5910 (jim_thompson5910):
btw, you say "or" instead of "and"
OpenStudy (anonymous):
-1/5
jimthompson5910 (jim_thompson5910):
better, so its
p > 3/5 or p < -1/5
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OpenStudy (anonymous):
k thx... i dont need help on the other question cuz i understand it now... ur a good helper... help me next time!! lol
jimthompson5910 (jim_thompson5910):
I'm glad you think so and that it's starting to click for you