Find the slope of the line containing the given pair of points. If the line is undefined, state so (1, -9) and (-2, -3)
use point slope formula... (y2-y1)/(x2-x1) and if slope is undefined line will be parallel to x axis and slope would be infinity
how do i fine them
well you've to substitute the points on the point slope form...like (-3-(-9))/(-2-1)..and in case of undefined slope you need not to find anything since infinite slope defines a line parallel to Y axis
ihave to make a graph
for what?
as per your question you're done ....with slope
Plot each of the points on an x y coordinate system and draw a line through the points using a straight edge.
ok i did
|dw:1344876563869:dw| this is a rough sketch
its a straight line
Yes
a bit more down hill from left to right than the rough sketch
ok never mine i'm not understanding this
i'm so lost
How so? Are you using graph paper to plot?
how do i find a slope
use point slope formula that i have shown earlier
Find the slope of the line containing the given pair of points. If the line is undefined, state so. Please be sure to show all of your work. (1, -9) and (-2, -3)
Well, you are given two points. When you put those points on a graph and draw a line between them, you will basically have a slope to that line.
it'll be 6/-3=-2
If it is level, you have no slope, or zero. If it is straight up, it is undefined. All of the other numbers are in the middle.
I think of riding my bicycle on the line from left to right. If it is hard to pedal up the hill, it is a big positive slope.
Once you get the concept that slope is how steep the hill is, then you use ghazi's equation for slope. \[m=(y2-y1)/(x2-x1)\]
You could say that your (1,-9) point is the (x1, y1) point and that the (-2, -3) point is your (x2, y2) point. Or the other way around, it will work itself out either way through the positive and negative signs.
Close, but your x's and y's are mixed up. (1,-9) is to the right one space and down 9 spaces from the origin.
ok
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