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Mathematics 15 Online
OpenStudy (anonymous):

Find the slope of the line containing the given pair of points. If the line is undefined, state so (1, -9) and (-2, -3)

OpenStudy (ghazi):

use point slope formula... (y2-y1)/(x2-x1) and if slope is undefined line will be parallel to x axis and slope would be infinity

OpenStudy (anonymous):

how do i fine them

OpenStudy (ghazi):

well you've to substitute the points on the point slope form...like (-3-(-9))/(-2-1)..and in case of undefined slope you need not to find anything since infinite slope defines a line parallel to Y axis

OpenStudy (anonymous):

ihave to make a graph

OpenStudy (ghazi):

for what?

OpenStudy (ghazi):

as per your question you're done ....with slope

OpenStudy (anonymous):

Plot each of the points on an x y coordinate system and draw a line through the points using a straight edge.

OpenStudy (anonymous):

ok i did

OpenStudy (ghazi):

|dw:1344876563869:dw| this is a rough sketch

OpenStudy (anonymous):

its a straight line

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

a bit more down hill from left to right than the rough sketch

OpenStudy (anonymous):

ok never mine i'm not understanding this

OpenStudy (anonymous):

i'm so lost

OpenStudy (anonymous):

How so? Are you using graph paper to plot?

OpenStudy (anonymous):

how do i find a slope

OpenStudy (ghazi):

use point slope formula that i have shown earlier

OpenStudy (anonymous):

Find the slope of the line containing the given pair of points. If the line is undefined, state so. Please be sure to show all of your work. (1, -9) and (-2, -3)

OpenStudy (anonymous):

Well, you are given two points. When you put those points on a graph and draw a line between them, you will basically have a slope to that line.

OpenStudy (ghazi):

it'll be 6/-3=-2

OpenStudy (anonymous):

If it is level, you have no slope, or zero. If it is straight up, it is undefined. All of the other numbers are in the middle.

OpenStudy (anonymous):

I think of riding my bicycle on the line from left to right. If it is hard to pedal up the hill, it is a big positive slope.

OpenStudy (anonymous):

Once you get the concept that slope is how steep the hill is, then you use ghazi's equation for slope. \[m=(y2-y1)/(x2-x1)\]

OpenStudy (anonymous):

You could say that your (1,-9) point is the (x1, y1) point and that the (-2, -3) point is your (x2, y2) point. Or the other way around, it will work itself out either way through the positive and negative signs.

OpenStudy (anonymous):

OpenStudy (anonymous):

Close, but your x's and y's are mixed up. (1,-9) is to the right one space and down 9 spaces from the origin.

OpenStudy (anonymous):

ok

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