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Integrate 2/(root 4 - e^(2t) )
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i think you use the sub: e^t = 2sin(theta) but im verifying that it works
or e^t=u ?
ok it will work yes that sub will work too but eventually you have to use a trig substitution
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should we take s=4-u^2 ?
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no...
wait u = e^t du = e^t dt \[\rightarrow \int\limits_{?}^{?} \frac{2}{u \sqrt{4-u^{2}}} du\]
ok..makes sense
then \[u = 2\sin \theta\] \[du = 2 \cos \theta d \theta \] \[\rightarrow \int\limits_{}^{}\frac{2}{(2\sin \theta)\sqrt{4-4\sin^{2} \theta}} (2\cos \theta) d \theta\] simplify
1/sin theta !
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yep
which means, we integrate sin^-1 theta....damn
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