Question

i will give medal
The vertices of a triangle are A(16, 0), B(9, 2), and C(0, 0).

Using fractions, indicate that the slopes of its sides are:

Slope of AB = a0

Slope of BC = a1

Slope of AC = a2

The slopes of its altitudes are:

Altitude AB = a3

Altitude BC = a4

Altitude AC = a5

i need the formula for side slopes and altitudes slopes.

Answer 1

its too long,i'll solve a part,try to solve the rest on your own

slope of AB=(yB-yA/xB-xA)=(2-0/9-16)=-2/7
altitude relative to AB is perpendicular to AB so its slope is 7/2

Answer 2

how did you find its altitude

Answer 3

how do you find the altitude

Answer 4

i will give another M3d41

Answer 5

product of slope of perpendicular lines =-1
thats why slope of altitude of AB is 7/2...(which is -1/(-2/7))

Answer 6

-1 divided by -2/7
???

Answer 7

\[\frac{-1}{\frac{-2}{7}}=\frac{7}{2}\]

Answer 8

isn't it?

Answer 9

on the calculator it shows as 3.5

Answer 10

7/2 is indeed 3.5

Answer 11

yes your right one more thing

Answer 12

is this slope correct?

bc= -2/-9

ac - 0/-16

Answer 13

-2/-9 is same as 2/9 = 0.2222 .....keep it as 2/9
-0/-16 = 0

Answer 14

ok thanks so much

Answer 15

and yes,u applied the formula correwctly

Answer 16

yesssssss

Answer 17

if u got it tell me the slope of altitude of AC

Answer 18

you said 0

Answer 19

that was slope of AC
now i am asking slope of altitude of AC

Answer 20

0

Answer 21

nopes ,remember product of slopes is -1,for perpendicular lines.

Answer 22

-1/0
?

Answer 23

yesss,-1/0
so what's exatly -1/0 ??

Answer 24

infinity

Answer 25

?

Answer 26

thats what google calculator said

Answer 27

infinity is correct :)

Answer 28

thanks

Answer 29

so now did u get all the answers?

Answer 30

yes but i had to type undefined instead of infinity but everything else was correct