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Simplify expression: (5+x^-1)/(25-x^-2)
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x/(5x-1)
you can use pure algebra with exponential n http://www.wolframalpha.com/otation, but if you really want to see what i going on, recall that \(b^{-n}=\frac{1}{b^n}\) and multiply \[(5+\frac{1}{x})(25-\frac{1}{x^2})\]
How exactly do you solve it? Could you explain how you got the answer?
you need to do four multiplications, just as you would if you had \((x+3)(x+4)\)
use x^-1=1/x and then you have (5+1/x)/(25-1/x^2)
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(5x+1)/ x/ (25x^2-1) /(x^2) this is equal to (5x+1)x^2/x(5x-1)(5x+1) wich is equal to x/(5x-1)
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