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Mathematics 8 Online
OpenStudy (anonymous):

Please help! geometry hw!

OpenStudy (anonymous):

OpenStudy (anonymous):

do you know the Pythagorean theorem?

OpenStudy (anonymous):

a2+b2=c2 12^2+11^2=rt 265 3^2+5^2= rt34 neither roots can be simplified.

OpenStudy (anonymous):

back

OpenStudy (anonymous):

there isn't any simplification going on here. the first problem is \[\sqrt{12^2 - 11^2}\]

OpenStudy (anonymous):

and the second one is \[\sqrt{3^2 + 5^2}\]

OpenStudy (anonymous):

if it was a perfect square there would be.

OpenStudy (anonymous):

if pigs had wings they could fly

OpenStudy (anonymous):

irrelevant

OpenStudy (anonymous):

There are a limited number of "Pythagorean triples" These are not.

OpenStudy (anonymous):

Thats redundant here.. This is simple geometry.

OpenStudy (anonymous):

I really don't know what to say. You can lead a horse to water but you can't make him drink??

OpenStudy (anonymous):

Lol alright fine im out

OpenStudy (anonymous):

So what's the answer? i'm confused!

OpenStudy (anonymous):

Sorry @nanaheads I got confused and thought all these comments were from you. According to the Pythagorean Theorem, in a right triangle with sides a, b and h, where h is the hypotenuse \[a^2 + b^2 = h^2\] and so \[a = \sqrt{h^2-b^2}\] In your first problem, h=12 and b=11. Use the second equation. In your second problem, a=3 and b=5. Use the first equation.

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