Let \( \cdot \) be an associative operation on a non empty set A with identity e. Suppose a,b,c and d are elements of A, b is the inverse of a, and d is the inverse of c. Prove that db is the inverse of ac
OK, so (d.b).(a.c)=(d.c).(a.b)=e.e=e, so by definition d.b is an inverse of a.b
I mean a.c
simple as that
yayyyyyyyy
Thanks :))))
well i have a question
it just said db and you computed it as \( d \cdot b\)
Like i just checked my book and i saw a hint compute (ac)(db) and (db)(ac)
I used the dot to refer back to the fact that we are dealing with an operation. A binary operation is actually a relation that maps ordered pairs to elements. I don't know if that answers your question, I was looking at the wikipedia page for binary operation and I lost my train of thought. Good material, though: http://en.wikipedia.org/wiki/Binary_operation
The book might have given such hint just because the defination says that if X and Y are inverse of each other, then X.Y=Y.X=Identity The X.Y=Y.X part is just to show that the group also follows commutative property also.......but again using simple manipulation as the 1st,u can prove the 2nd part also....
Gotcha.Thanksss guyyss :)
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