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Mathematics 19 Online
OpenStudy (anonymous):

ref or rref? im confused A =6 0 0 0 0 5 1 0 0 0 0 2 Which of the following statements is/are true? A. A is in row–echelon form. B. A is in reduced row–echelon form.

OpenStudy (anonymous):

please explain the difference between the two if you can

OpenStudy (anonymous):

rref like you can see each leading coeficient in the raw is the only non 0 coeficient of that column

OpenStudy (anonymous):

@Kudos

OpenStudy (anonymous):

A matrix (any matrix, not just an augmented matrix) is said to be in reduced row-echelon form if it satisfies all four of the following conditions. If there are any rows of all zeros then they are at the bottom of the matrix. If a row does not consist of all zeros then its first non-zero entry (i.e. the left most non-zero entry) is a 1 - This 1 is called a leading 1. In any two successive rows, neither of which consists of all zeroes, the leading 1 of the lower row is to the right of the leading 1 of the higher row. If a column contains a leading 1 then all the other entries of that column are zero. from " http://tutorial.math.lamar.edu/Classes/LinAlg/SolvingSystemsOfEqns.aspx ".

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

@mtaOS is right, I forgot that the leading coeficient should be 1 in rref

OpenStudy (anonymous):

Okay, so if it isnt a 1 ie. 3 then it is not an rref matrix

OpenStudy (anonymous):

right

OpenStudy (anonymous):

Can a matrix be in both forms?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

ah that makes sense, thanx guys

OpenStudy (anonymous):

yw

OpenStudy (amistre64):

all row reduced echelon form, are in row echelon form not all row echelon forms are row reduced echelon forms

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