Darlene kicks a soccer ball off the ground and in the air with an initial velocity of 34 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?

17.7 feet

18.1 feet

19.3 feet

20.2 feet

Question

Darlene kicks a soccer ball off the ground and in the air with an initial velocity of 34 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches?

 17.7 feet

 18.1 feet

 19.3 feet

 20.2 feet

anonymous · Answer

H(t) represents the trayectory of the ball. With v and s beying some constants you shopuld find. 
Since at t=0 height would be 0, it means s=0.
H'(t) would be it's velocity. H'(t)=-32t+v
Since it says that fot t=0 H'(t)=34  it means that v=34, so H(t) = −16t2+34t+s

anonymous · Answer

got it?

anonymous · Answer

no im, confused

anonymous · Answer

$$ H(t) = −16t^2 + vt + s$$ you told $v=34$ in this line 
"with an initial velocity of 34 feet per second"

anonymous · Answer

and you are also told that $s=0$ in this line 
"off the ground" because when the ball is on the ground, the height is 0

anonymous · Answer

H(t) = −16t2 + vt + s
is a parabola. It looks something like this:|dw:1344954690585:dw|