Where does the graph of y = 6x2 + 5x − 6 cross the x-axis? (−1/6, 0) and (6, 0) (1/6, 0) and (−6, 0) (2/3, 0) and (−3/2, 0) (−2/3, 0) and (3/2, 0)
0 = 6x2 + 5x − 6
Hint: The \(\mathsf{x-intercept}\).
And then I am too lazy to solve it for you. Give it a try.
they 6x2 is 6x^2
the*
Yep.
parth i cant believe u
Partkohli is correct, you are looking for the x intercepts, also known as roots or solutions
if it is factorable, you can factor it to solve it. you can always use the quadratic formula to find the solutions as well (it works 100% of the time) you can also, look at the graph to determine the solutions. Many ways to do this problem
\[0 = ax^2 + bx +c\]\[\Rightarrow\qquad x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] \[0 = 6x^2 + 5x − 6\]\[\Rightarrow\qquad x=\frac{-(5)\pm\sqrt{(5)^2-4\times(6)\times(-6)}}{2\times(6)}\]
ok thanks i can solve that
to get from \[y= 6x^2 + 5x − 6\]to \[0 = 6x^2 + 5x − 6\] i have used the fact that the \(x\)-intercept is when y=0
Join our real-time social learning platform and learn together with your friends!