What is the partial sum 25 ∑ -5+13i i=12
3,297 3,630 3,976 4,335
the sum notation is a linear transformation ... if i recall the definition of a linear transformation correctly
∑ -5+13i -5∑ + 13 ∑ i -5(range) + 13 (range(n*(n+1)/2))
range would be defined as: high - low + 1
or, we could translate i from 12 to 0 and add 12 to each i to keep it the same
25 ∑ -5+13i i=12 13 ∑ -5+13(i+12) i=0 there are so many ways we can approach this
i still dont understand it really
if you wanna brute math it into submission, the most fundamental means would be to copy the equation itself a few times such that for each copy you replace the "i" by the values from 12 to 25; then add them all up
-5+13(12)= -5+13(13)= -5+13(14)= -5+13(15)= .... -5+13(25)=
so after i get each total, do i add all the totals up?
yep
okay
that is the long way to do it, but it works in the end :)
thank you....could i do that for every equation ?
1: -5+13(12) 2: -5+13(13) 3: -5+13(14) 4: -5+13(15) 5: -5+13(16) 6: -5+13(17) 7: -5+13(18) 8: -5+13(19) 9: -5+13(20) 10:-5+13(21) 11:-5+13(22) 12:-5+13(23) 13:-5+13(24) 14:-5+13(25) -------------- -5(14) + 13(14)(12+25)/2
you can do it for reasonably small equations by hand. the more terms there are the better it is to know the shorter methods
thank you. I found the answer
cool :) what was it ?
3297
yay!! i got that too, so either we both did it right, or we both got it terribly wrong lol
i have another question, and if you dont mind can you please help me?
lol
go ahead and ask
Given the sequence 3, 9, 15, which of the following is equivalent to 8 ∑ An n=5
does it say if the sequence of arith or geoM?
no it doesn't
a1 = 3 a2 = 3 + 6 = 9 a3 = 9 + 6 = 15 so this looks to be that we are adding the same value each time to get the next term. we call that an arithmetic sequence
if we can form the general equation that defines this sequence, we can then do the same thing as the we did on the first question
okay
a1 = 3 a2 = 3 + 6 = 9 a3 = 3 + 6 + 6 3 + 6(2) = 15 an = 3 + 6(n-1) is the equation we seek
okay...im going to try and solve it and see what i get
\[\large \sum_{n=5}^{8}3+6(n-1)\]
1: 3+6(4) 2: 3+6(5) 3: 3+6(6) 4: 3+6(7) ------- 3(4)+6(4)(4+5+6+7)
i got 144
12+24(22) = 12+ 528 is going to be a little bit bigger than 144
144 is one of my answer choices . the highest one is 168
really? 1: 3 2: 9 3: 15 4: 21 .......... 5: 27 6: 33 7: 39 8: 45 ------ 144 hmmm, i wonder what i was thinking about then :)
lol...yea i am about to submit the answers after i finish one more question and i will let you know if it was right or not
They were right...thank you
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