All of the triangles in the figure below are congruent. What is the area of the figure? Note that all measurements are in centimeters.
where is the figure?
Note that the apothem shown is equal to 2 square root of three.
it's 2* \[\sqrt{3}/4 * (side)^2\]
twice of the area of equilateral triangle
um, also, what does apothem mean exactly?
a line from the center of a regular polygon at right angles to any of its sides
like a radius on a circle?
ok, so, what is the side? I multiply 2 times square root of 3/4 times S squared, is that what you're saying?
yess
what is the formula that you're trying to give me? The one above doesn't make sense, can you spell it out for me?
see there are two triangles ....if you ain't consedering it equilateral triangle then just go through this...you have the altitude you need to find the base use pythagoras theorem |dw:1344969634066:dw| \[x= \sqrt{4^2-3^2}\]= sqrt7
then for this triangle area of triangle would be 2*(1/2*base*height) and for two triangles as shown in figure you have to multiply this again by 2 that is 2*2*(1/2*base * height)
hope it is clear now :)
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