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Mathematics 13 Online
OpenStudy (anonymous):

All of the triangles in the figure below are congruent. What is the area of the figure? Note that all measurements are in centimeters.

OpenStudy (ghazi):

where is the figure?

OpenStudy (anonymous):

OpenStudy (anonymous):

Note that the apothem shown is equal to 2 square root of three.

OpenStudy (ghazi):

it's 2* \[\sqrt{3}/4 * (side)^2\]

OpenStudy (ghazi):

twice of the area of equilateral triangle

OpenStudy (anonymous):

um, also, what does apothem mean exactly?

OpenStudy (ghazi):

a line from the center of a regular polygon at right angles to any of its sides

OpenStudy (anonymous):

like a radius on a circle?

OpenStudy (anonymous):

ok, so, what is the side? I multiply 2 times square root of 3/4 times S squared, is that what you're saying?

OpenStudy (ghazi):

yess

OpenStudy (anonymous):

what is the formula that you're trying to give me? The one above doesn't make sense, can you spell it out for me?

OpenStudy (ghazi):

see there are two triangles ....if you ain't consedering it equilateral triangle then just go through this...you have the altitude you need to find the base use pythagoras theorem |dw:1344969634066:dw| \[x= \sqrt{4^2-3^2}\]= sqrt7

OpenStudy (ghazi):

then for this triangle area of triangle would be 2*(1/2*base*height) and for two triangles as shown in figure you have to multiply this again by 2 that is 2*2*(1/2*base * height)

OpenStudy (ghazi):

hope it is clear now :)

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