Question

solve for x: (e^4)^x*e^x^2=e^12

Answer 1

\[(e ^{4})^{x}\times e ^{x ^{2}}=e ^{12}\]

Answer 2

did i make it clear now ?

Answer 3

you have e^(4x+x^2)=e^12 to be equal should x^2+4x=12 solve it and it is

Answer 4

\[e ^{4x+x ^{2}}=e ^{12}\]
by exponent rules
later just take logarithm of bouth sides
and solve equation for x

Answer 5

oh thanks. i got it. can you help me with this aswel ? \[e ^{4x-9}=\frac{ 1 }{ e }\]

Answer 6

here u have 4x-9=-1

Answer 7

\[1/e=e ^{-1}\]
the rest is the same like in previous one

Answer 8

bec0use 1/e=e^-1

Answer 9

oh thank you guys :) appreciate it a lot