What is the solution of \[\log _{2x+3} 125 = 3\]
x=1/3 x=1 x=7/3 x=4
Lets rewrite it as \( (2x+3)^3=125 \)
2\[2x^{3} + 27 = 125\]
nope \((2x+3)^3 = (2x+3)(2x+3)(2x+3) \)
Do you multiply from there?
hmm I am thinking of taking an easier route
Let w=2x+3 so we can rewite it as \( w^3=125\) did u follow that?
what would do after
u didnt follow lol ok ill just continue maybe ull follow what i did once u see the full picture
probably lol
\( \large \sqrt[3]{w^3 }= \sqrt[3]{125} \) \( \large w= \sqrt[3]{125} \) \(w=5\)
I basically tried to isolate the w or in other words solve for w
Sadly, thats not one of the answers
now we know that w=2x+3 so lets subsitute our w for 2x+3 2x+3=5 2x=2 x=1
hahahah that is your answer lol
1 is an answer
U so didnt follow what i did but alright at least u got the answer :)
thanks lol
What is the solution to the equation \[\frac{ 1 }{\sqrt{8}} = 4^{(m+3)}\]
x=-15/4 x=-11/4 x=5/4 x=9/4
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