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solve: log2(x2−x−2)=2
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\[ \log_{2}(x ^{2}-x-2)=2 \]
if you raise each as a power of 2 \[2^{\log_{2}(x^2 - x -2)} = 2^2\] you end up with x^2 - x - 2 = 4 since \[a^{\log_{a}(u)} = u\] now you should be able to solve the equation
x = 3, -2
thank you guys :)
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