Mathematics
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OpenStudy (anonymous):
1. Please simplify sqrt(x^7).
13 years ago
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OpenStudy (anonymous):
\[\sqrt{x^7} =\sqrt{x^2*x^2*x^2*x}\]
can you tell me what the \[\sqrt{x^2} \]is?
13 years ago
OpenStudy (anonymous):
Can you please explain this to me?
13 years ago
OpenStudy (anonymous):
x
13 years ago
OpenStudy (anonymous):
well ok do you know what the square root of 4 is?
\[\sqrt{4}\]
13 years ago
OpenStudy (anonymous):
2
13 years ago
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OpenStudy (anonymous):
Its 2
13 years ago
OpenStudy (anonymous):
all you have do to is ask yourself what two number of the same multiply together give me 4 in this case 2 since 2x2=4
13 years ago
OpenStudy (anonymous):
But how would you do that if the number is 7?
13 years ago
OpenStudy (anonymous):
Do you know why the square root of 4
is 2?
13 years ago
OpenStudy (anonymous):
there a rule for numbers like 7
13 years ago
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OpenStudy (anonymous):
Whats the rule?
13 years ago
OpenStudy (anonymous):
beside 7 isnt a perfect squirt
13 years ago
OpenStudy (anonymous):
I know this
13 years ago
OpenStudy (anonymous):
the sqrt of 7 is 7 since 7 isnt a perfect quare
13 years ago
OpenStudy (anonymous):
So the answer is 7 to my questions?
13 years ago
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OpenStudy (anonymous):
yes
13 years ago
OpenStudy (anonymous):
That's not the answer.
13 years ago
OpenStudy (anonymous):
Then someone please explain to me step by step how to get the answer.
13 years ago
OpenStudy (anonymous):
\[\sqrt{x^7}=\sqrt{x^2*x^2*x^2*x}=\sqrt{x^2}*\sqrt{x^2}*\sqrt{x^2}*\sqrt{x}\]
13 years ago
OpenStudy (anonymous):
Sqrt(x*x*x*x*x*x*x)
So, each x has to has a pair to leave the "square root"
So, x-x x-x x-x x
So there are three pairs and one left over
SO! x^3 sqrt(x)
:) hope it helped!
13 years ago
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OpenStudy (anonymous):
Can you tell me what \[\sqrt{x^2}\]
13 years ago
OpenStudy (anonymous):
yeap just x
13 years ago
OpenStudy (anonymous):
I know you know I want to the Original asker to tell me what it is
13 years ago
OpenStudy (anonymous):
because when you multiply back x and x you get x sq
13 years ago