Okay... here we go. a/b(2x-12)=c/d
what are you looking to do/find?
x
i got ad/2bc + 6=x
How though?
What do you need to solve for?
ok so you're going to distribute the b, so that you get 2xb-12b. Then rewrite your equation with that in place of what you had before
Then after that, you need to cross multiply
When you do that, you should get AD=C(2Bx-12B). tell me if you get confused on that.
okay hold on. and im solving for x.
Wait where does the a go?
the A gets multiplied by the D...then you multiply the C by (2Bx-12B) to get the answer i gave you above
This is so confusing.
lol, give me a minute and ill type it up for you
okay thanks.
\[a \div b(2x-12)= c \div d\]
so this is your original equation. draw this with the a in the numerator and the c in the numerator. Then multiply the A and the D. See how they're across from each other? thats cross multiplying. then multiply the C and the (2Bx-12B) and put that answer on the other side of the equal sign
okay! I get it. thanks.
That's not exactly right @rjeffries96
The equation is this: \(\large\frac{a(2x-12)}{b} = \frac{c}{d}\)
Here are the steps: 1. Multiply both sides by variable b 2. Divide both sides by variable a 3. Add 12 to both sides 4. Divide both sides by 2 5. variable x is isolated
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