What are the x-intercept(s) of the graph of y + 20 = x2 − x? (−5, 0) and (4, 0) (5, 0) and (−4, 0) (−5, 0) and (−4, 0) (5, 0) and (4, 0)
Always for finding x intercept, put y = 0.. \[0 + 20 = x^2 - x\] Subtract 20 both the sides: \[x^2 - x - 20 = 0\] Now factorize it to find x..
is it the third option
Show me that what you got after factorization??
ok give me a sec i sorta did this in a rush
let me try again see if i get it right this time
Take your time..
i got 1/2?
How ??
I said to make factors..
x is aprox 4.944 and x is aprox -3.944
so then second option?
Yes second is good but your method is not right..
oh can you explain
\[x^2 - x - 20 = 0\] \[x^2 - 5x + 4x - 20 = 0\] \[(x-5)(x+4) = 0\] \[x - 5 = 0 \implies x = 5\] \[x + 4 = 0 \implies x = -4\]
\[(5,0) \; \; and \; \; (-4, 0)\]
oh i see what i did wrong i was following the quadratic formula instead of factoring srry
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