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dentify the discontinuities, graph, and find the zeros of each rational function. f(x)=2x^2+5x-12/x+4
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we know the discontinuity is where \(x+4=0\) i.e. \(x=4\)
zeros will be where \[2x^2+5x-12=0\] maybe it factors
i suck at factoring, but this one is \((2x-3)(x+4)\)zeros are easy enough to find what else do you need?
oh and a graph i believe.
did he answer it???
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Yes, he gave you the complete answer, like last time. The discontinuity is at x+4=0 or x=-4. I.e. the function is undefined at x=-4. The remaining points form a straight line where y=2x-3. The problem is similar to the previous one.
well is is -4 or 4 ?
it's 4...
It's x+4=0, which means that the discontinuity is at x=-4.
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