Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

I want to know about Complex numbers completely. anybody can help me

OpenStudy (anonymous):

i = sqrt(-1) ,so i^2 = -1

OpenStudy (unklerhaukus):

a complex number has two components \[z=a+ib\] where\[i=\sqrt{-1}\] and\[a,b\in \mathbb R\]

OpenStudy (anonymous):

try counting to infinity without stopping.

hero (hero):

There's like an entire advanced mathematics course fully dedicated to studying complex numbers. I think you can find it on MIT courseware.

OpenStudy (anonymous):

\(i=+\sqrt{-1},~-i=-\sqrt{-1}\)

OpenStudy (unklerhaukus):

\[\large{\frac 1i}\small{=\frac1i\times1{}}\]\[\qquad=\frac1i\times\frac{-i}{-i}\]\[\qquad=\frac{-i}{-i^2}\]\[\qquad=\frac{-i}{-(-1)}\]\[\qquad=\frac{-i}{1}\]\[\large {\large{\frac 1i}=-i}\]

OpenStudy (unklerhaukus):

conceder the solutions to this equation\[x^2+1=0\]

OpenStudy (anonymous):

did you read it?

OpenStudy (anonymous):

I did.

OpenStudy (unklerhaukus):

good link @panlac01

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!