Please help :/ Two Precalc/Trig similar problems that I'm having trouble with. Click attached

Question

anonymous · Answer

attachment

anonymous · Answer

Are you able to view the pictures?

anonymous · Answer

is it de answer for first pic 15 i?

lgbasallote · Answer

$$\large 3 \overline A + 6\overline B \implies 3(3 \hat i - 4 \hat j) + 6(\hat i + 2\hat j) \implies 9 \hat i - 12 \hat j + 6 \hat  i + 12 \hat j  \implies 15 \hat i $$
right?

anonymous · Answer

@sharm How did you get that answer? @igbasallote is it correct?

anonymous · Answer

just use distribution. that is assuming that i is a variable.

lgbasallote · Answer

...well seeing as i have a solution...i would say what i said was right...

anonymous · Answer

I can't view your final answer... Your post is cut off towards the end

lgbasallote · Answer

exactly..

anonymous · Answer

he didn't show the final answer, because you have to simplify it.  he merely gave you the steps.

lgbasallote · Answer

you can try finding the answer from $$\large 9 \hat i  - 12\hat j + 6\hat i + 12 \hat j$$
what do you think is the answer?

anonymous · Answer

i did exactly like Igbasallote did..that was de method i used,,,

anonymous · Answer

Ok @panlac01 I just didn't realize. Now I understand.

lgbasallote · Answer

as for the second one...it's a little more tricky

anonymous · Answer

Thank you @igba and @sharm :) And yes, the second is tricky

anonymous · Answer

ur welcome ...nyway wats de answer for de second one??

lgbasallote · Answer

first you need to find the value of $\overline A$ and $\overline B$
$$\large \overline A = 3\hat i - 4\hat j$$so...
$$\large \overline A = \sqrt{ (3)^2 + (-4)^2}$$
$$\large \overline B = \hat i + 2\hat j$$ so...
$$\large \overline B = \sqrt{ (1)^2 + (2)^2}$$

now.. $$\theta = \tan^{-1}\left(\frac{\overline A}{\overline B} \right)$$
do you get that?

lgbasallote · Answer

i know that looks confusing...so feel free to ask anything about what i just wrote

anonymous · Answer

ooh yea...i gt it..

ganeshie8 · Answer

you can use dot product for 2nd q

anonymous · Answer

pythagorean theorem is a nifty tool

anonymous · Answer

is it v have to choose the nearest ans???

anonymous · Answer

Thank you @igbasallote I really appreciate it

anonymous · Answer

Thank you everyone else :)

lgbasallote · Answer

i think it's about time i admit this.....it's LGBASALLOTE..not igbasallote

anonymous · Answer

Oops. My bad.

anonymous · Answer

No wonder sometimes it doesn't highlight blue when I mention your name

anonymous · Answer

is there a manual on how to manipulate the equation tool here?